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A heavy small sized sphere is suspended ...

A heavy small sized sphere is suspended by a string of length l . The sphere rotates uniformly in a horizontal circle with the string making an angle `theta` with the vertical. Then the time period of this conical pendulum is-

A

T = 2`pi`

B

`T = 2pi sqrt(((lsin theta)/(g)))`

C

`T = 2pi sqrt(((lcos theta)/(g)))`

D

`T = 2pi sqrt(((l)/(g)))`

Text Solution

Verified by Experts

The correct Answer is:
C
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