`._(90) Th ^(234) overset( nalpha , n "_"beta^(0))(to) ._(83) Bi^(214) ,`Find n & n

Explanation

To solve the problem, we need to determine the values of \( n \) (the number of alpha particles emitted) and \( m \) (the number of beta particles emitted) in the decay of Thorium-234 (\( _{90}^{234}Th \)) to Bismuth-214 (\( _{83}^{214}Bi \)).

### Step-by-Step Solution:

1. **Identify the changes in mass number and atomic number:**
- The mass number of Thorium-234 is 234, and the mass number of Bismuth-214 is 214.
- The atomic number of Thorium is 90, and the atomic number of Bismuth is 83.

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