What is the energy released by fassion of 1 g of `U^(235)`? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

Explanation

No . Of atom in 1 gm of `U^(235) = (N_(A))/( 235)`
Energy released `= (N_(A))/( 235) xx 200 MeV`
`= 6.023 xx (10^(23))/( 235) xx 200 MeV`
`=5xx 10^(23) MeV = (5 xx 10^(23)) (1.6 xx 10^(-13) J)`
`= 8 xx 10^(10) J = (8xx 10^(10))/( 3.6 xx 10^(6)) kWh = | 2.5 xx 10^(4)` kWh