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Mass of Helium nucleus = 4 . 00015 amu...

Mass of Helium nucleus = 4 . 00015 amu and mass of a proton =1 .0073 amu mass of neutron= 1.0087 amu Calculate the mass defect and energy liberated in formation of He nucleus and also evaluate binding energy of `._(2)He^(4)` nucleus.

Text Solution

Verified by Experts

The correct Answer is:
`Delta m = 0.305 u`
`Delta m = (2m_(p) + 2m_(n)) - M , Delta E = (Delta m) 931 MeV = E_(B)`
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