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If 200 MeV energy is released in the fis...

If `200 MeV` energy is released in the fission of a single `U^235` nucleus, the number of fissions required per second to produce `1` kilowatt power shall be (Given `1 eV = 1.6 xx 10^-19 J`).

Text Solution

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`18.7 xx 10^(14)`
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