Calculate the excess pressure withing a bubble of air of radius 0.1 mm in water. If te bubble had been formed 10 cm below the water surface on a day when the atmospheric pressure was `1.013xx10^(3)Pa` then what would have been the total pressure inside the bubble? surface tension of water `=73xx10^(-3)N//m`

Explanation

Excess pressure
`P_("in")=P_(atm)+hdeltag+(2T)/(r)`
`=(1.013xx10^(3))+(10xx10^(-2)xx10^(3)xx9.8)+1460`
`=101300+980+1460=103740=1.037xx10^(5)Pa`