A light beam travelling in the `x`-direction is described by the eectirc field `E_(y) = (300 V//m) sin omega(t - x//c)`. An electron is constrained to move along the `y`-direction with a speed of `2.0 xx 10^(7) m//sec`. Find the maximum electric force and the maximum magnetic force on the electron.

Explanation

The maximum value of magnetic field `(B_(0))` is given by
`B_(0)=E_(0)/c=300/(3xx10^(8))=10^(-6)` tesle
The magnetic field will be along Z-axis The maximum magnetic force on the electron is given by
` F_(e) = qE_(0) = (1.6 xx10^(–19)) ×x 300`
`=4.8 xx 10^(-17)`N
The maximum magnetic force on the electron is
`F_(b) = abs(q(vxxB))= "q v "B_(0)`
` = (1.6 x10^(–19)) x(2.0 x10^(7)) x(10^(–6))`
`= 3.2 xx10^(-18)`N