If `(n !)/(2!(n-2)!) and (n !)/(4!(n-4)!)` are in the ratio `2:1` , find the value of `ndot`

Explanation

To solve the problem, we need to find the value of \( n \) such that the expressions \( \frac{n!}{2!(n-2)!} \) and \( \frac{n!}{4!(n-4)!} \) are in the ratio \( 2:1 \).

### Step-by-Step Solution:

1. **Set up the equation based on the given ratio**:
\[ \frac{\frac{n!}{2!(n-2)!}}{\frac{n!}{4!(n-4)!}} = \frac{2}{1} \]
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