sin4A=4sin A cos^(3)A-4cos A sin^(3)A

Prove that sin 4A=4 sin A cos^(3) A-4 cos A sin^(3) A

Prove that: "sin" 4A=4 sin A cos^(3)A-4 cos A "sin"^(3)A .

sin4x=4sin x cos^(3)x-4cos x sin^(3)x

The value of 4 sin A cos^(3) A- 4 cos A sin^(3) A is equal to

The value of 4 sin A cos ^(3) A-4 cos A sin ^(3)A

Statement II: 4sin A cos^(3)A-4cos A sin^(3)A=cos4A Which of the above statements is correct?

sin4A=4cos^(3)A sin A-4sin^(3)A cos A

The value of 4 sin A cos ^3 A -4 cos sin^3 A is equal to

2 sin A cos ^(3) A-2 sin ^(3) A cos A= ................. A) sin 4A B) 1/2 sin 4 A C) 1/4 sin 4A D) 1/8 sin 4A