Charge on the ring is given as `lambda=lambda_(0)cos theta` C/m .Find dipole moment of the ring

The linear charge density of a uniform semicircular wire varies with theta shown in the figure as lambda=lambda_(0)costheta if R is the radius of the loop ,of the charge on the wire is

A charge q is spread uniformly over an isolated ring of radius 'R'. The ring is rotated about its natural axis and has magnetic dipole moment of the ring as M. Angular velocity of rotation is

A circle of radius a has charge density given by lambda=lambda_(0)cos^(2)theta on its circumference, where lambda_(0) is a positive constant and theta is the angular position of a point on the circle with respect to some reference line. The potential at the centre of the circle is

The linear charge density on a ring of radius R is lambda=lambda_0 sin (theta) where lambda_0 is a constant and theta is angle of radius vector of any point on the ring with x-axis. The electric potential at centre of ring is

the following diagram represents a semi circular wire of linear charge density lambda=lambda_(0)sin theta where lambda_(0) is a positive constant.The electric potential at o is (take k=(1)/(4piepsilon_(0))

A thin non-conducting ring of radius R has a linear charge density lambda=lambda_(0) cos theta , where theta is measured as shown. The total electric dipole moment of the charge distribution is

A semicircular wire is uniformly charged with linear charge density dependent on the angle theta from y -direction as lambda=lambda_(0) |sin theta| , where lambda_(0) is a constant. The electric field intensity at the centre of the arc is

The linear charge density on a dielectric ring of radius R vanes with theta as lambda = lambda_0 cos theta//2 , where lambda_0 is constant. Find the potential at the center O of the ring [in volt].