A projectile is fired from surface of earth at `30^(@)` above horizontal with speed `u=sqrt((GM_(c))/(R))` where `M_(c)` is mass of earth R is radius of earth Find maximum height of the projectile above earth surface

A rocket of mass M is launched vertically from the surface of the earth with an initial speed V= sqrt((gR)/(2)) . Assuming the radius of the earth to be R and negligible air resistance, the maximum height attained by the rocket above the surface of the earth is (R)/(X) where X is:

A projectile of mass m is fired from the surface of the earth at an angle alpha = 60^(@) from the vertical. The initial speed upsilon_(0) is equal to sqrt((GM_(e))/(R_(e)) . How high does the projectile rise ? Neglect air resistance and the earth's rotation.

A roket of mass M is launched vertically upwards from trhe surface of the earth with an intial speed v . Assuming the radius of the earth to be R and negligible air resistance, the maximum height attained by the roket above the surface of the earth is

A projectile is fired from the surface of earth of radius R with a velocity k upsilon_(e) (where upsilon_(e) is the escape velocity from surface of earth and k lt 1) . Neglecting air resistance, the maximum height of rise from centre of earth is

A particle of mass 'm' is raised from the surface of earth to a height h = 2R. Find work done by some external agent in the process. Here, R is the radius of earth and g the acceleration due to gravity on earth's surface.