Prove that: `("tan"(A+B))/("cot"(A-B))=\ (tan^2A-tan^2B)/(1-tan^2Atan^2B)`

Prove that: (tan(A+B))/(cot(A-B))=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

Prove that: tan(A+B)tan(A-B)=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

Prove: (tan A+tan B)/(cot A+cot B)=tan A tan B

Prove that tan(A+B+C)=(tan A+tan B+tan C-tan A tan B tan C)/(1-tan A tan B-tan B tan C-tan C tan A)

Prove that tan(A-B)=(tan A-tan B)/(1+tan A*tan B) , if A=60° & B=45°.

By using above basic addition/ subtraction formulae, prove that (i) tan (A+B)=(tan A+tan B)/(1-tan A tan B) , (ii) tan (A-B)=(tan A-tanB)/(1+tan A tan B) (iii) sin2theta=2sintheta costheta , (iv) cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1 (v) tan 2theta=(2 tan theta)/(1-tan^(2) theta)

(b-c)/(a) = (tan B/2-tan( c/2))/(tan B/2+tan C/2)

If sin2A=lambda sin2B prove that ((tan(A+B))/(tan(A-B)))=(lambda+1)/(lambda-1)

Prove: (cot A+tan B)/(cot B+tan A)=cot A tan B

In any Delta ABC, prove that : ((a-b)/(c))=(tan((A)/(2))-tan((B)/(2)))/(tan((A)/(2))+tan((B)/(2)))