In a triangle ABC Let BC=a CA=b AB=c and `r_(1) r_(2)&r_(3)` be the radii of ex-circles opposite to vertices A B&C respectively. If `r_(1) =2r_(2)=2r_(3)` then `3(a/b)`=

In a triangle with sides a,b,c,r_(1)

In DeltaABC, R, r, r_(1), r_(2), r_(3) denote the circumradius, inradius, the exradii opposite to the vertices A,B, C respectively. Given that r_(1) :r_(2): r_(3) = 1: 2 : 3 The sides of the triangle are in the ratio

In DeltaABC, R, r, r_(1), r_(2), r_(3) denote the circumradius, inradius, the exradii opposite to the vertices A,B, C respectively. Given that r_(1) :r_(2): r_(3) = 1: 2 : 3 The greatest angle of the triangle is given by

In a !ABC , if r_(1) =2r_(2) =3r_(3) , then a:b:c =

In DeltaABC, R, r, r_(1), r_(2), r_(3) denote the circumradius, inradius, the exradii opposite to the vertices A,B, C respectively. Given that r_(1) :r_(2): r_(3) = 1: 2 : 3 The value of R : r is

In DeltaABC, let b=6, c=10and r_(1) =r_(2)+r_(3)+r then find area of Delta ABC.

In triangleABC , If r_(1), r_(2), r_(3) are exradii opposites to angles A,B and C respectively. Then (1/r_(1) +1/r_(2)) (1/r_(2)+1/r_(3)) (1/r_(3)+1/r_(1)) is equal to

In triangle ABC if r_(1)=3,r_(2)=10,r_(3)=15 then c=