A cyclic quadrilateral KPRQ is inscribed a circle with centre 0. A tangent ST touches the point P. If `/_PRQ =130^(@)` then `/_QPT=`? (Take S and K on the same side of PQ )

In a circle 0 is the centre.Tangent TPT touches the point P and AP is the chord if /_POA=130^(@) then the value of /_APT will be (Take T and A on the same side of OP )

In a circle 0 is the centre.Tangent TPT' touches the point P and AP is the chord if /_POA=130^(@) then the value of /_APT will be (Take T and A on the same side of OP )

In a circle 0 is the centre.Tangent TPT' touches the point P and AP is the chord if /_POA=130^(@) then the value of /_APT will be (Take T and A on the same side of OP)

In a circle O is the centre.Tangent TPT' touches the point P and AP is the chord if /_POA=130^(@) then the value of /_APT will be (Take T and A on the same side of OP )

In a circle, O is the center. Tangent TPT' touches the point P and AP is the chord , if ∠POA =130∘ then the value of ∠APT will be [Take T and A on same side of OP]

In the given figure,PQ is a chord of a circle with centre O and PT is a tangent.If /_QPT=60^(@) find /_PRQ

In Figure 4,PQ and PR are tangents drawn to a circle with centre O from an external point P . If /_PRQ=70^(@), then find /_QPR and /_OQR

In Figure PQ is a chord of a circle with centre O and PT is a tangent. If QPT =60^@ so, find PRQ.

PQ is a tangent to a circle with centre O at the point P . If DeltaOPQ is an isoceless triangle, then /_OQP is equal to

In the figure, seg AB is a diameter of a circle with centre C. Line PQ is a tangent , which touches the circle at point T. seg AP _|_ line PQ and seg BQ _|_ line PQ. Prove that, seg CP ~= seg CQ.