A body covers a distance of 4m under the action of force F = (17 – 4x)N where x is the distance in metres. The work done by the force is

A body moves a distance of 10 m under the action of force F=10N. If the work done is 25 J, the angle which the force makes with the direction of motion is

A particle of mass 2 kg starts motion at time t = 0 under the action of variable force F = 4t (where F is in N and t is in s). The work done by this force in first two

A body covers a distance of 5 m along a straight line under the action of a fore of 10N. What is the angle made by the force with the direction of motionof the body if the work done is 25J?

An object of mass 8 kg starts to move from rest under the action of a variable force F=3xN where x is the distance (in m) covered by the object. If initially, the position of the object is x = 2 m, then find its speed ("in m s"^(-1)) when it crosses x = 10 m.

A rigid body moves a distance of 10m along a straight line under the action of a force 5N. If the work done by this force on the body is 25 joules, the angle which the force makes with the force makes with the direction of motion of the body is:

The distance x covered by a body of 2 kg under the action of a force is related to time t as x=t^(2)//4 . What is the work done by this force in 2 seconds ?

Under the action of a force F = Cx, the position of a body changes from 0 to x. The work done is

A body moves a distance of 10 m along a straight line under an action of 5 N force. If work done is 25 J, then angle between the force and firection of motion of the body will be :