The ring has zero resistance.The cells are 5V 2`Omega` each R is 4`Omega` .Find current through R .

In the circuit shown in Fig. the emf of the sources is equal to xi = 5.0 V and the resistances are equal to R_(1) = 4.0 Omega and R_(2) = 6.0 Omega . The internal resistance of the source equals R = 1.10 Omega . Find the currents flowing through the resistances R_(1) and R_(2) .

Two cells each of emf 10 V and each 1Omega internal resistance are used to send a current through a wire of 2Omega resistance. The cells are arranged in parallel. Then the current through the circuit

A cell of emf 2V and internal resistance 4 Omega is connected across a parallel combination of two resistors of resistance 10 Omega and 20 Omega . Find the current through each resistor using Kirchhoff's laws.

A battery of 6 V internal resistance 0.5 Omega is joined in parallel with another of 10 V and internal resistnace 1 Omega . The combination sends a current through an external resistance of 12 Omega . Find the current through each battery.

The circuit diagram has two cells epsilon_(1) and epsilon_(2) with emf 4 V and 2V respectively, each one having an internal resistance 2 Omega . The external resistance R is of 8 Omega . Find the magnitude and the direction of current flowing through the two cells

A battery of emf 6V internal resistance 5 Omega is joined in parallel with another cell of emf of 10V and internal resistance 1Omega and the combination is used to send current through a resistor of 12Omega . Calculate the current through each battery.