An electric current is passed through an aqueous solution of a mixture of alanine (isoelectric point 6.0 ) , glutamic acid (3.2) and arginine (10.7) buffered at pH 6.What is the fate of the three acids?

An electric current is passed through an aqueous solution ( buffered at pH=6.0) of a alanine (pl=6.0) and arginine (pI=10.2) . The two amino acids can be separated because

1F of electricity is passed through 10 L of a solution of aqueous solution of NaCl . Calculate the pH of the solution.

A mixture of which 0.2M aqueous solutions will form a precipitate the dissolves in 6M nitric acid:

A current of 0.75 A is passed through an acidic solution of CuSO_4 for 10 minutes. The vlume of oxygen liberated at anode (at STP) will be.

Which is a stronger acid - a solution with pH 6 or a solution with pH 3?

An amino acid reacts with 10ml 0.05MNaOH and the final solution has pH=2.30 When 20ml of these base is added in the resulting solution.The pH become 9.7 .Identify the amino acid and calculate the isoelectric point of the amino acid.This amino acid is prepared by the reaction of compound (X) with NH_(3) and further hydrolysis with HCN compound (X) is less C atom containing compound that gives postitive iodoform test and positive Fehling's solution test. Isoelectric point of the amino acid is: