The point `(-2m ,m+1)` is an interior point of the smaller region bounded by the circle `x^(2)+y^(2)=4` and the parabola `y^(2)=4x` .Then `m` belongs to the interval

The number of integral values of a for which the point (-2a,a+1) will be interior point of the smaller region bounded by the circle x^(2)+y^(2)=4 and the parabola y^(2)=4x is:

If (-2a,a+1) lies in the interior (smaller region) bounded by the circle x^2+y^2=4 and the parabola y^2=4x , then

The area of the smaller region bounded by the circle x^(2) + y^(2) =1 and the lines |y| = x +1 is

If (9a,6a) is a point interior to the region bounded by the parabola y^(2)=16x and the line x=9 then

Using integration find the area of the region bounded by the parabola y^(2)=4x and the circle 4x^(2)+4y^(2)=9

If the point (k+1,k) lies inside the region bounded by the curve x=sqrt(25-y^(2)) and y- axis.Then .k belongs to the interval

Find the area of the region bounded by the parabola x^(2)=4y and the line x=4y-2

Find the area of the region bounded by the parabola y^(2)=2x and the line x-y=4

Find the area of the region bounded by the parabola y=x^(2) and y=|x|