Home
Class 12
MATHS
The line y=2x-k(k!=0) meets the parabola...

The line y=2x-k(`k!=0)` meets the parabola `y=x^(2)-4x` at points A and B .If `angleAOB=pi/(2)` then value of k is (0 is origin)

Promotional Banner

Similar Questions

Explore conceptually related problems

The line y=2x-k, k ne 0 , meets the parabola y=x^(2)-4x at points A and B. If angle AOB=pi//2 , then value of k is

The line y=2x-k(k!=0) meets the parabola y=x^(2)-4x at points A and B.If (|__AOB)/(2) then value of k is (0 is origin) 212781762

Suppose the line y=kx-7 intersects the parabola y=x^(2)-4x at points A and B. If angleAOB=pi//2 , then k is equal to

Line y=2x-b cuts the parabola y=x^(2)-4x at points A and B. Then the value of b for which angleAOB is a right is (where O is origin) _________ .

Line y=2x-b cuts the parabola y=x^(2)-4x at points A and B. Then the value of b for which angleAOB is a right is (where O is origin) _________ .

If the line y=2x+k tangent to the parabola y=x^(2)+3x+5 then find 'k' is

If the line 2x+3y+k=0 touches the parabola x^(2)=108y then k =

If the line x-3y+k=0 touches the parabola 3y^(2)=4x then the value of k is

If the line y=x+k is a normal to the parabola y^(2)=4x then find the value of k.