(2n+1) G.M.s are inserted between 4 and 2916 .Then the `(n+1)^(th)` G.M.is equal to

n A.MI's are inserted between n and 3n+2 then 10 th A.M. is

m A.M. and 3 G.M. are inserted between 3 and 243 such that 2^(nd) GM= 4^(th) AM then m=

Insert 7 G. M.'s between 2 and 162

If 'n'A.M's are inserted between 7 and 71 in such a way that 5^(th ) A.M is 27 then the value of n=

If n arithmetic means xare inserted between 1 and 31 such that the 7^(th) mean: the (n+1)^(th) mean =5:9 then prove that n=14

Let n AM's are inserted between - 7 and 65 If the ratio of 2^(nd) and 7^(th) means is 1:7 , then n is equal to

n A.M.'s are inserted between 1 and 31 such that the ratio of the 7 th and (n-1) th means is 5:9. Find n.