Let `f(x) = (x-p)^2+ (x -q)^2 + (x - r)^2`. Then `f(x)` has a minimum at `x = lambda`, where `lambda` is equal to

If f(x) = [x] + [-x], x ne 2 = lambda, x = 2 , then f is continuous at x = 2, provided lambda is equal to :

If f : R rarr R is defined by f(x) = {((cos3x-cosx)/x^(2), x ne 0),(lambda, x = 0):} and if f is continuous at x = 0 then lambda is equal to

If f(x)=|(x,lambda),(2lambda,x)| , then f(lambdax)-f(x) is equal to

Let f(x)={x^(2),x 0} ,then for what value of (k,p),f(x) has a minimum

f(x) = {:([x] + [-x] x ne 2),(" "lambda " " x = 2 ):} f(x) is continuous at x = 2 then lambda =

Let the function f(x) be defined as below f(x)=sin^(-1)lambda+x^(2) when 0 =1.f(x) can have a minimum at x=1 then value of lambda is

Let the function f(x) be defined as below f(x)=sin^(-1) lambda+x^2 when 0 =1 . f(x) can have a minimum at x=1 then value of lambda is