A function f is defined by `f(x) = int_0^pi cos t cos(x-t)dt,0 <= x <= 2 pi` then which of the following.hold(s) good?

A function is defined by f(x) = int_0^pi cos t cos(x-t)dt,0 <= x <= 2 pi then which of the following equals?

A function f is defined by f(x)=\ int_0^picostcos(x-t)dt ,\ 0lt=xlt=2pi then find its minimum value.

If a differentiable function f(x) satisfies f(x)=int_(0)^(x)(f(t)cos t-cos(t-x))dt then value of (1)/(e)(f''((pi)/(2))) is

A differentiable function satisfies f(x)=int_(0)^(x){f(t)cost-cos(t-x)}dt. Which is of the following hold good?

Let function F be defined as f(x)= int_1^x e^t/t dt x > 0 then the value of the integral int_1^1 e^t/(t+a) dt where a > 0 is

Difference between the greatest and least values opf the function f (x) = int _(0)^(x) (cos ^(2) t + cos t +2) dt in the interval [0, 2pi] is K pi, then K is equal to:

Difference between the greatest and least values opf the function f (x) = int _(0)^(x) (cos ^(2) t + cos t +2) dt in the interval [0, 2pi] is K pi, then K is equal to:

Let function F be defined as f(x)=int_(1)^(x)(e^(t))/(t)dtx>0 then the vaiue of the integral int_(1)^(1)(e^(t))/(t+a)dt where a>0 is

Let f(x) be a differentiable function satisfying f(x)=int_(0)^(x)e^((2tx-t^(2)))cos(x-t)dt , then find the value of f''(0) .