[" (iv) "x-3y-7=0],[quad 3x-3y-15=0]

Which of the following pairs of linear equations has unique solution,no solution,or infinitely many solutions.In each there is unique solution ,find it by using cross multiplication method.(iv)3x-3y-7=0 3x-3y-15=0

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solution, no solution, or ininitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x-3y-7=0 and 3x-3y-15=0

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. : - x-3y-7=0 , 3x-3y-15=0

Solve [2x+3y-7=0],[3x+2y-8=0]

Which of the following pairs of linear equations has a unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross-multiplication method: x-3y-7=0 3x-3y-15=0

Which of the followings pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x-3y-7=0 3x-3y-15=0

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x- 3y-7=0 3x- 3y- 15= 0

" If the lines "5x-3y+15=0" and "5x+3y-15=0" forms a triangle with "X-" axis. Then the radius of circum circle is "

If the lines 5x+3y-15=0 and 3x+5y-15=0 cut both the axes at A,B,C and D then