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If a group of `n` distinct objects, the number of arrangements of 4 object is 12 times the number of arrangements of 2 objects, then the number of objects is (a)`10` (b) `8 `(c) `6 `(d) none of these

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According to the question :
`n_(P_4)=12xxn_(P_2)`
`⇒(n!)/((n−4)!)=12×(n!)/((n−2)!)`
`⇒((n−2)!)/((n−4)!)=12`
`⇒(n−2)(n−3)=4xx3`
`⇒ n-2 = 4`
`⇒ n=6`
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