Robert is selling televisions at an electronics store. The televisions normally cost $545 each but are being sold at an 8% discount. What is the minimum number of televisions Robert must sell if he wants to meet his quota of $1,00,000 in total sales?

Answer

To solve the problem step by step, we will follow these calculations:

**Step 1: Calculate the selling price of one television after the discount.**

The original price of the television is $545. The discount is 8%.

First, we calculate the amount of the discount:
\[ \text{Discount} = \frac{8}{100} \times 545 = 0.08 \times 545 = 43.6 \]

Now, we subtract the discount from the original price to find the selling price:
\[ \text{Selling Price} = 545 - 43.6 = 501.4 \]

**Step 2: Determine the total sales quota.**

Robert wants to meet a sales quota of $100,000.

**Step 3: Calculate the minimum number of televisions Robert must sell.**

To find the number of televisions Robert needs to sell, we divide the total sales quota by the selling price of one television:
\[ \text{Number of TVs} = \frac{\text{Total Sales Quota}}{\text{Selling Price}} = \frac{100,000}{501.4} \]

Calculating this gives:
\[ \text{Number of TVs} \approx 199.45 \]

**Step 4: Round up to the nearest whole number.**

Since Robert cannot sell a fraction of a television, we round up to the nearest whole number. Therefore, he needs to sell:
\[ \text{Minimum Number of TVs} = 200 \]

Thus, the minimum number of televisions Robert must sell to meet his quota is **200**.

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