8a^(3)-27b^(3)-1-18ab...

`8a^(3)-27b^(3)-1-18ab`

Text Solution

Verified by Experts

The correct Answer is:

`(2a-3b-1)(4a^(2)+9b^(2)+1+6ab-3b+2a)`

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8x^(3)-27

8x^(3)+27

Factorise : 8a^(3)-b^(3)+1+6ab

a^(3)-b^(3)+1+3ab

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x^(3)+8y^(3)+27z^(3)-18xyz

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If a + b + 1 = 0 , determine the value of (a^(3)+b^(3)-3ab+1).

1+8x^(3)+18xy-27y^(3)

Factorise 27a ^(3) + b ^(3) + 8c^(3) -18 abc using identity.

CALCUTTA BOOK HOUSE-FACTORISATION-EXERCISE 2.2 (C Factorise the following polynomials )

8a^(3)-27b^(3)-1-18ab
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1+8x^(3)+18xy-27y^(3)
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1+b^(3)+8c^(3)-6bc
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Factorise : a^(6)-5a^(3)+8
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Factorise : a^(6)-18a^(3)+125
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Factorise : x^(3)+(1)/(x^(3))+(47)/(64)
04:00
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Factorise : 2sqrt(2)a^(3)+8b^(3)-27c^(3)+18sqrt(2)abc
04:50
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x^(3)+8y^(3)+27z^(3)-18xyz
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x^(3)-8y^(3)+64z^(3)+24xyz
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(x-y)^(3)+(y-z)^(3)+(z-x)^(3)
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(2a-3b)^(3)+(4c-2a)^(3)+(3b-4c)^(3)
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Factorise : ((x)/(2)+y+(z)/(3))^(3)+((x)/(3)-(2y)/(3)+z)^(3)-((5x)/(6)...
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(1-x)^(3)-(1-y)^(3)+(x-y)^(3)
02:40
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(5a-7b)^(3)+(9c-5a)^(3)+(7b-9c)^(3)
02:46
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(3a-2b)^(3)+(2b-5c)^(3)+(5c-3a)^(3)
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(2x-y)^(3)-(x+y)^(3)+(2y-x)^(3)
03:42
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(a-2b)^(3)+(c-a)^(3)+(2b-c)^(3)
02:14
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