A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number.

A die is thrown three times, if the first throw is a four, find the chance of getting 15 as the sum.

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both will get the prize. If A throws first then the probability of B winning the prize is -

In a game of chance a player throws a pair of dice and scores points equal to the difference between the numbers on the two dice. Winner is the person who scores exactly 5 points more than his opponent. If two players are playing this game only one time, then the probability that neither of them wins to

Four persons A, B, C and D throw an unbiased die, turn by turn, in succession till one gets an even number and win the game. What is the probability that A wins the game if A begins ?

A and B play alternately with a pair of unbiased dice. A wins if he throws 6 before B throws 7 and B wins if he throws 7 before A throws 6. If A begins, show that his chance of winning is (30)/(61) .

A and B play for a prize of Rs 99 the prize is to be won by a player who first throes a '3' with one die A first throes and if he fails B throws and if he fails A again throws and so on find their respective expectations

A and B play alternately with an unbiased die. He who first throws a 'six' wins. If A begins, show that his chance of winning is (6)/(11) .

A and B alternatively toss a fair coin. The first once to throw a head wins. If A starts find their respective probabilities of winning.

In a game, a man wins Rs 100 if he gets 5 or 6 on a throw of a fair die and loses Rs 50 for getting any other number on the die. If he decides to throw the die either till he gets a five or a six or to a maximum of three throws, then his expected gain/loss (in rupees) is:

A gambler throws two unbiased dice and stands to loss Rs 5 if he fails to throwl a 5 to win Rs 10 if he throws on e five and to win Rs 25 if he throws fives is the game fair ?