A `10kg` block rests on a `5kg` bracket as shown in figureThe `5kg` breaket rests on a horizontal surface The coefficient of frictionbetween the `10kg` block and the braket on wich it rests are `mu_(s) = 0.40 and mu_(k) = 0.30`

If the `10 kg` block is not to slide on the braket , the corresponding acceleration of the `5 kg` braacket is

Answer

(a) 24 N ; (b) `1.6 m//s^(2)`

Explanation

(a) F.B.D of block

`F_("max") = mu_(S)N`
(b) F.B.D of bracket
`2F - F = M xx a`