A circular disc with a groove along its diameter is placed horizontally . A block of mass 1 kg is placed as shown . The coefficient of friction between the block and all surfaces of groove in contact is `mu = 2//5` . The disc has an acceleration of `25 m//s^(2)` . find the acceleration of the block with respect to disc .

Answer

(a) `10 m//s^(2)`

Explanation

N + ma sin `theta = "mg cos" theta`
N = ( mg cos `theta - "ma sin" theta )`
Acceleration of mass w.r. to disc
` a_(0) = (( "mg sin " theta + "ma cos" theta - muN)/(m))`