A block slides down a rough inclined plane of slope angle `theta` with a constnat velocity. It is then projected up the same plane with an intial velocity v the distance travelled by the block up the plane coming to rest is .

Answer

`v_(0)^(2)// ( 4 "g sin" theta)`

Explanation

`v^(2) = v_(0)^(2) - 2as `
`v_(0)^(2) = 2as `
`s = (v_(0)^(2))/(2 xx 2 "g sin " theta )`
As a = g sin `theta` + g cos `theta xx mu`
= g sin `theta + ("sin" theta)/("cos" theta) xx "g cos" theta `
a = 2 g sin `theta`