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Pushing force making an angle theta to t...

Pushing force making an angle `theta` to the horizontal is applied on a block of weight W placed on a horizontal table . If the angle of friction is `phi` , magnitude of force required to move the body is equal to :

A

`W "cos" phi //"cos" (theta-phi)`

B

`W "sin" phi //"cos" (theta+ phi)`

C

`W "tan" phi//"sin" (theta- phi)`

D

`W "sin" theta // "g tan" (theta - phi)`

Text Solution

Verified by Experts

The correct Answer is:
B


F cos `theta = mu N`
F cos `theta = "tan" phi [omega + F "sin" theta]`
`F = ((omega "tan" phi)/("cos" theta - "sin" theta * "tan" phi))`
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GRB PUBLICATION-FRICTION AND CIRCULAR MOTION -OBJECTIVE QUESTIONS ( only one choice is correct )
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