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Coefficient of static friction between t...

Coefficient of static friction between the two blocks in Fig. 7.124 is `mu` and the table is frictionless . Maximum horizontal force which can be applied on the lower such that the blocks move together , is :

A

`mu m_(1) g`

B

`mu m_(2)g`

C

`mu (m_(1) - m_(2))g`

D

`mu ( m_(1) + m_(2))g`

Text Solution

Verified by Experts

The correct Answer is:
D
Common acceleration = `((F)/(m_(1) + m_(2)))` as a = `mu` g
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GRB PUBLICATION-FRICTION AND CIRCULAR MOTION -OBJECTIVE QUESTIONS ( only one choice is correct )
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