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Two thin roads are moving perpendicularl...

Two thin roads are moving perpendicularly as shown in the figure. If the friction acting between them is `F_(R )` then the unit vector in the direction of friction force acting on the rod lying along x-axis is

A

`((-hati - 2hatj))/(sqrt5)`

B

`((hati + 2hatj))/(sqrt5)`

C

`((3 hati + 2 hatj))/(sqrt13)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
Relative velocity of rod on y-axis with respect to x-axis is `v hati + 2 v hatj`.
The direction of friction on rod along x - axis is along relative velocity `hatf = ( hati + 2 hatj)/(sqrt5)`
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