A block lying on a long horizontal conveyer belt moving at a constant velocity receives a velocity `v_(0) = 5m//s` relative to the ground in the direction opposite to the direction of motion of the conveyer. After `t = 4s`, the velocity of the block becomes equal to the velocity of the belt. The coefficient of friction between the block and the belt is `mu = 0.2`. Determine the velocity v of the conveyer belt.

Options

A. 3 m/s
B. 5 m/s
C. 4 m/s
D. 7 m/s

Answer

A

Explanation

`v_("Block") = v_(0) - at `
`a = mu g `