A particle of weight W rests on a rough inclined plane which makes an angle `alpha` with the horizontal . If the coefficient of static friction `mu = 2 "tan" alpha` , find the horizontal force H acting transverse to the slope of the plane when the particle is about to slip :

Options

A. W `sqrt3 cos alpha`
B. `W sqrt3 sin alpha`
C. `(W sin alpha)/(sqrt3)`
D. `(W cos alpha)/(sqrt3)`

Answer

B

Explanation

W sin `alpha + H cos alpha = mu H " " …. (i)`
`H sin alpha + H = W cos alpha " " …… (ii)`
By solving Eqns. (i) and (ii) , we get H .