A block rests on a rough inclined plane ...

A block rests on a rough inclined plane making an angle of `30^(@)` with horizontal. The coefficient of static friction between the block and inclined plane is `0.8` . If the frictional force on the block is `10 N`, the mass of the block in `kg` is `(g = 10 m//s^(2))`

`2.5`

`4.0`

`1.6`

`2.0`

Text Solution

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The correct Answer is:

f = Mg sin `theta`

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