A block of weight 5 N is pushed against ...

A block of weight 5 N is pushed against a vertical wall by a force 12 N . The coefficient of friction between the wall and block is `0.6` . Find the magnitude of the force exerted by the wall on the block :

12 N

13 N

17 N

16 N

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Verified by Experts

The correct Answer is:

Reaction `=sqrt((12)^(2)+5^(2)) =sqrt169`

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