A closed chain `A` of mass `m` = 0.36kg is attached to a vertical rotating shaft by means of thread showin in fig. and rotated with a constant angular velocity `omega=35rad//s`. The thread forms an angle `theta=45^(@)` with the vertical. Then the tension of the thread is

Answer

5

Explanation

For circular motion of the chain

`T sin theta = m omega^(2)r ` and `T cos theta = mg`
`therefore tan theta = (omega^(2)r)/(g)` or `r = (g tan theta)/(omega^(2))`