Block A and B are connected by a rod of negligible mass as shown in Fig . 7.199 . The mass of each block is `170` kg . The coefficient of friction between inclined plane and blocks A and B are 0.2 and 0.4 respectively . The tension in the rod is found to be 50 x newtons, the value of x is :

Answer

3

Explanation

As the rod is light , tension at all points in the rod will remain the same .
Block A : `" " 170 " g sin" theta - f_(A) - N = 170a " " …. (i)`
Block B : `" " 170 " g sin " theta + N - f_(B) = 170a " " ….. (ii)`
Where `f_(A) = 0.2 xx 170 "g cos" theta` and `f_(B) = 0.4 xx 170 "g cos" theta`

Solving , `a = (35)/(17) ms^(-2)`
Substituting value of `f_(A)` and a in WEqn . (i) ,
`N = 150 N = 50 xx 3 ` newton
`therefore " " x = 3`