When `(0,0)` shifted to `(3,-3)` the co-ordinates of `P, Q, R` are `(5,5),(-2,4) and (7,-7)` in the new system are `A, B, C` then area of triangle `ABC` in sq units is

When (0,0) is shifted to (sqrt(7),2+sqrt(3)) the coordinates of P(5,5), Q(-2,4) and R(7,-7) in the new system are A, B, C . Then area of /_\ABC is:

When (0,0) is shifted to (3,-3) then the points P(5,5),Q(-2,4) and R(7,-7) are changed as A,B,C and if the area of triangle ABC is k then (86)/(k) is

If the co - ordinate of the triangle P(4,3) Q (7,-1) and R (9,3) is then find the Area of triangle PQR and also find the types of triangle ?

Point R divides line joining A(-5, 1) and B(3, 5) in the ratio lambda:1 . The co - ordinates of P and Q are (1, 5) and (7, 2) respectively. If the area of the triangle PQR be 2 sq. units, then the value of lambda is

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. Area of the triangle ABC is (in sq. units)

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. Area of the triangle ABC is (in sq. units)

The co-ordinates of A,B,C are (6,3),(-3,5)and (4,-2) respectively and P is the point (x,y) show that , (area of the /_\PBC)/(area of the /_\ABC)=|(x+y-2)/7|

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 (i) Area of the triangle ABC (in sq. units) is-

If (2,3) are the coordinates of a point P in the new system when the origin is shifted to (-3,7) then the original coordinates of P are