" (i) "(k,0),(4,0),(0,2)

Find the values of k if area of triangle is 4 sq. units and vertices are (k,0),(4,0),(0,2)

Find values of k if area of triangle is 4sq. units and vertices are (k,0)(4,0),(0,2)

Find the value of k if the area of the triangle is 4 sq. units whose vertices are : (k, 0), (4, 0), (0, 2).

Find the value of k, if the area of triangle is 4 square unit and vertices are P(k,0),Q(4,0),R(0,2)

The area of triangle with vertices (K, 0), (4,0), (0, 2) is 4 square units, then value of K is

If area of triangle is 35 sq. units with vertices (k,0), (4,0) and (0,2) then k is :

Find the value of k,if area of triangle is 4 sq. units and vertices arw (k,0),(4,0) and(0,2) using determinant.

Using determinant find the values of k so that the area of the triangle with vertices at the points (k,0),(4,0) and (0,2) is 4 sq units.