[" iii.The sum of the areas of two squares is "400" sq.m.If the difference between their perimeters is "],[16m," find the sides of two squares."]

Solve the following problems : The sum of the areas of two squares is 400 sq m. If the difference between their perimeters is 16 m. Find the sides of two squares.

Sum of the areas of two squares is 400 cm. If the difference of their perimeters is 16 cm, find the sides of the two squares.

Sum of the areas of two squares is 400 cm. If the difference of their perimeters is 16 cm, find the sides of the two squares.

Sum of the areas of two squares is 400cm. If the difference of their perimeters is 16cm, find the sides of the two squares.

Sum of the areas of two squares is 640 m^2 . If the difference of their perimeters is 64m, find the sides of the two squares.

The sum of the areas of two squares is 640 m^(2) . If the difference in their perimeters be 64 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.