" If "x^(2/3)+y^(2/3)=2," find "(dy)/(dx)" at "(1,1)

1:Ify=x^(3)+3xy^(2)+3x^(2)y, find (dy)/(dx)

" 3.Find "(dy)/(dx)" if "x^(2)y^(x)=1

If y^(5)+xy^(2)+x^(3)=4x+3, then find (dy)/(dx) at (2 1)

y=1/(x-2/3) find dy/dx

y=(x^2+1/x^2)^3 find dy/dx

If y= (x^2 +3)/( x^3 + 2x) , find (dy)/( dx) at x=1 .

Given that y= (3x -1)^(2) + (2x -1)^(3) , find (dy)/( dx) and the points on the curve for which (dy)/(dx)=0