" (c) "27a^(6)+125b^(3)

If 3a + 5b + 4c= 0 , show that: 27a^(3) + 125b^(3) + 64 c^(3) = 180 abc

Factorize the expression of the following (i)a^(3)+27(ii)27a^(3)+125b^(3)(iii)(2a+1)^(3)+(a-1)^(3)

Factorize: 27a^(3)+125b^(3)

(a) Factorize 27a^(3) + 125 x^(3)

Factorise : (i) 125a^(3)+(1)/(8) " " (ii) 8a^(3)-27b^(3)

Factorise : (i) 125a^(3)+(1)/(8) " " (ii) 8a^(3)-27b^(3)

Factorise each of the following : 27y^(3) + 125z^(3)

1 ? 27 64 125

1 ? 27 64 125

Factorize : 64a^(3)+125b^(3)+240a^(2)b+300ab^(2)(8)/(27)x^(3)+1+(4)/(3)x^(2)+2xx^(3)+8y^(3)+6x^(2)y+12xy^(2)8a^(3)-27b^(3)-36a^(2)b+54ab^(2)x^(3)-12x(x-4)-64