" (iv) "6u^(2)+17u+12

Calculate the the binding energy per nucleon for a _6C^(12) nucleus. Nuclear mass of _6C^(12) = 12.000000 a.m.u.,mass of hydrogen nucleus =1.007825 a.m.u. and mass of neutron = 1.008665 a.m.u.

If f(u) = 1/(u^(2)+u-2) , where u = 1/(x-1) , then the points of discontinuity of f are x = …..

Let f be a composite function.of x defined by f(u)=(1)/(u^(3)-6u^(2)+11u-6) where u(x)=(1)/(x) .Then the number of points x where f is discontinuous is

If u_(0) = 8 , u_(1) = 3 , u_(2) = 12 , u_(3) = 51 , then the value of Delta^(3) u_(0) is

The binding energy of ._(17)^(35 )Cl nncleus. Take atomic mass of ._6^(12) C as 12.000 an u Take R_(0) =1.2 xx 10-^(15) m .

If u_(n) = cos^(n) alpha + sin^(n) alpha , then the value of 2 u_(6) - 3 u_(4) +1 is :

Calculate the (i) mass defect, (ii) binding energy and (iii) the binding energy per nucleon of ""_(6)^(12)C nucleus. Nuclear mass of ""_(6)^12C = 12. 000000 u, mass of proton=1.007825 u and mass of neutron=1.008665 u.

If u_(1), u_(2), u_(3),… form a G.P. with common ratio k, find the sum of u_(1)u_(2) + u_(2)u_(3)+….+u_(n)u_(n+1) in terms of u_(1) and k.