[" 18.In "/_ABC,AB=AC" .Side "BC" is produced "],[[" to "D" .Prove that "],[qquad (AD^(2)-AC^(2))=BD*CD]]

In Delta ABC, AB= AC . Side BC is produced to D. Prove that (AD^(2)-AC^(2))=BD*CD .

In triangle ABC, AB=AC and BD is perpendicular to AC. Prove that : BD^(2)-CD^(2)=2CDxxAD

In an isosceles triangle ABC, AB = AC and D is a point on BC produced. Prove that : AD^(2)=AC^(2)+BD.CD

In an isoscles Delta ABC, AB= AC and D is a point on BC. Prove that AB^(2)-AD^(2)=BD*CD .

In an isosceles triangle ABC with AB = AC, BD is perpendicular from B to side AC. Prove that BD^(2)-CD^(2)=2CD.AD

In AD bot BC , prove that AB^(2)+CD^(2)=BD^(2)+AC^(2)

In Figure 2,AD perp BC. Prove that AB^(2)+CD^(2)=BD^(2)+AC^(2)

In /_ABC,AB=AC and D is any point on BC , prove that AB^(2)-AD^(2)=BD.CD

ABC is a triangle in which AB = AC and D is any point on BC. Prove that: AB^(2)- AD^(2) = BD. CD

In angle ACD=90^(@) and CD bot AB . Prove that (BC^(2))/(AC^(2))=(BD)/(AD)