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The correct order of heat of combustions...

The correct order of heat of combustions of the following hydrocarbon is :
`underset(P)Pent-1-ene " " underset(Q)Pentane " " underset(R)neopentane" "underset(S)isopentane`

A

`PgtQgtRgtS`

B

`QgtSgtRgtP`

C

`PgtQgtSgtR`

D

`SgtRgtRgtQgtP`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of heat of combustion for the given hydrocarbons (Pent-1-ene, Pentane, Neopentane, and Isopentane), we need to analyze the stability of each compound based on their structure and branching. The heat of combustion is inversely related to the stability of the compound; more stable compounds release less heat upon combustion. ### Step-by-Step Solution: 1. **Identify the Compounds**: - P: Pent-1-ene (an alkene) - Q: Pentane (an alkane) - R: Neopentane (a branched alkane) - S: Isopentane (a branched alkane) 2. **Understand Stability and Heat of Combustion**: - The heat of combustion is inversely proportional to the stability of the compound. More stable compounds will have lower heat of combustion. - Stability increases with branching in alkanes. The more branched the alkane, the more stable it is. 3. **Rank the Compounds by Stability**: - **P (Pent-1-ene)**: As an alkene, it is less stable than alkanes. - **Q (Pentane)**: A straight-chain alkane, more stable than alkenes but less stable than branched alkanes. - **R (Neopentane)**: Highly branched alkane, very stable. - **S (Isopentane)**: Moderately branched alkane, more stable than straight-chain but less stable than neopentane. 4. **Determine the Order of Heat of Combustion**: - Since heat of combustion is inversely proportional to stability: - **P (Pent-1-ene)** will have the highest heat of combustion (least stable). - **Q (Pentane)** will have a lower heat of combustion than P. - **S (Isopentane)** will have a lower heat of combustion than Q. - **R (Neopentane)** will have the lowest heat of combustion (most stable). 5. **Final Order**: - The correct order of heat of combustion from highest to lowest is: - P (Pent-1-ene) > Q (Pentane) > S (Isopentane) > R (Neopentane) ### Conclusion: Thus, the correct order of heat of combustion for the given hydrocarbons is: **P > Q > S > R**

To determine the correct order of heat of combustion for the given hydrocarbons (Pent-1-ene, Pentane, Neopentane, and Isopentane), we need to analyze the stability of each compound based on their structure and branching. The heat of combustion is inversely related to the stability of the compound; more stable compounds release less heat upon combustion. ### Step-by-Step Solution: 1. **Identify the Compounds**: - P: Pent-1-ene (an alkene) - Q: Pentane (an alkane) - R: Neopentane (a branched alkane) ...
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