`Ph-underset(CH_(3))underset(|)(C )H-CH_(2)-CH_(3)overset(Cl_(2))underset(hv)rarr"Products" overset("Fractional")underset("Distillation")rarr "Fractions"`,
No of products and no of fractions are respectively:

Options

A. 6,5
B. 6,4
C. 5,4
D. 6,3

Explanation

To solve the question regarding the chlorination of the given hydrocarbon in the presence of sunlight and the subsequent fractional distillation, we will follow these steps:

### Step 1: Identify the Reactant
The reactant is pH-CH(CH3)-CH2-CH3, which is a derivative of toluene (methylbenzene).

### Step 2: Understand the Reaction
The reaction involves chlorination in the presence of sunlight (hv), which indicates a free radical substitution mechanism. In this process, chlorine (Cl2) will replace hydrogen atoms from the alkyl chain (the part of the molecule that is not aromatic).

### Step 3: Determine Possible Products
Since the chlorination can occur at different positions on the alkyl chain, we will consider the following positions:
1. Chlorination at the terminal CH3 group (producing pH-CH(CH2Cl)-CH2-CH3)
2. Chlorination at the CH2 group (producing pH-CH(CH3)-CH(Cl)-CH3)
3. Chlorination at the second CH3 group (producing pH-CH(CH3)-CH2-CH2Cl)

Each of these products can potentially have stereoisomers if they have chiral centers.

### Step 4: Identify Chiral Centers
1. The product from the second position has a chiral center (pH-CH(CH3)-CH(Cl)-CH3).
2. The product from the third position also has a chiral center (pH-CH(CH2Cl)-CH2-CH3).

### Step 5: Count the Total Products
- The first product (no chiral center) contributes 1.
- The second product (with a chiral center) contributes 2 (enantiomers).
- The third product (with a chiral center) contributes 2 (enantiomers).
- The fourth product (no chiral center) contributes 1.

Adding these together gives:
1 (from the first product) + 2 (from the second) + 2 (from the third) + 1 (from the fourth) = 6 total products.

### Step 6: Determine the Number of Fractions from Fractional Distillation
Fractional distillation will separate the products based on their boiling points. Since we have:
- 1 product without a chiral center,
- 2 enantiomers from the second product,
- 2 enantiomers from the third product,
- 1 product without a chiral center,

This results in a total of 4 distinct fractions (the two enantiomers from the chiral centers are counted separately).

### Final Answers
- Number of products: 6
- Number of fractions: 4

### Summary
Thus, the final answer to the question is:
- Number of products: **6**
- Number of fractions: **4**