`Ph-CH=CH=Ph underset(CCI_(4))overset(CI_(2))rarr X overset(2NaNH_(2))rarrYoverset(H_(2),Pd-CaCO_(3))rarrZ`
Identify product (Z) of the reaction.

Options

A.
B.
C.
D. `Ph-C-=C-Ph`

Explanation

To identify the product (Z) of the given reaction sequence, let's break down the steps involved:

### Step 1: Identify the Starting Material
The starting material is an alkene: Ph-CH=CH=Ph, which is a compound with two phenyl groups (Ph) attached to a conjugated diene.

### Step 2: Reaction with Chlorine (Cl2 in CCl4)
The first reaction involves the addition of chlorine (Cl2) in carbon tetrachloride (CCl4). This reaction is an anti-addition across the double bond of the alkene.

- **Product X**: The product of this reaction will be a dichlorinated compound:
- Structure: Ph-CH(Cl)-CH(Cl)-Ph

### Step 3: Reaction with Sodium Amide (2NaNH2)
Next, the product X undergoes a reaction with sodium amide (2NaNH2). In this reaction, the two chlorine atoms and the two hydrogen atoms from the adjacent carbon atoms will be eliminated, resulting in the formation of a triple bond.

- **Product Y**: The product after this elimination will be:
- Structure: Ph-C≡C-Ph (a phenyl-substituted alkyne)

### Step 4: Hydrogenation with Lindlar's Catalyst (H2, Pd-CaCO3)
Finally, the alkyne (Product Y) is subjected to hydrogenation using Lindlar's catalyst (H2, Pd-CaCO3). This type of hydrogenation selectively converts alkynes to cis-alkenes.

- **Product Z**: The product after this hydrogenation will be:
- Structure: Ph-CH=CH-Ph (a cis-alkene)

### Final Answer
The product (Z) of the reaction is **Ph-CH=CH-Ph**, which is a cis-stilbene.

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