[x+2y-z=0],[3x+y+z=7],[2x-y+2x=7]}[" 0."quad x-3y],[quad 5x+y]

x+2y-3z=0,3x+3y-z=5,x-2y+2z=1

4x -5y-11z=12,. x-3y+z=1 2x + 3y-7z = 2

x+y+z=1 x-2y+3z=2 5x-3y+z=3

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

What should be added to x y+y z+z x to get x y-y z-z x ? (a) -2x y-2y z-2z x (b) -3x y-y z-z x (c) -3x y-3y z-3z x (d) 2x y+2y z+2z x